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k^2+64=16k
We move all terms to the left:
k^2+64-(16k)=0
a = 1; b = -16; c = +64;
Δ = b2-4ac
Δ = -162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$k=\frac{-b}{2a}=\frac{16}{2}=8$
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